Given Network = 172.23.12.0
Subnet Mask = /23 = 255.255.254.0
We calculate the Block Size for third Octet = 256-254
= 2
Read MoreTherefore the Subnetwork in third octet will be = 0,2,4,6,8,10,12.......254
Now We can write Subnetwork
172.23.0.0
172.23.2.0
172.23.4.0
172.23.6.0
172.23.8.0
172.23.10.0
172.23.12.0 to 172.23.13.255
172.23.14.0
Answer: Valid Host Range = 172.23.12.1 to 172.23.13.254 for Network 172.23.12.0
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